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1113330314777 is a prime number
BaseRepresentation
bin10000001100110111101…
…010000110111000011001
310221102200220101220212212
4100030313222012320121
5121220100030033102
62211242404244505
7143302235351012
oct20146752067031
93842626356785
101113330314777
1139a184a3586a
1215b9300a0735
1380ca97300b5
143bc57a58009
151de60dedc52
hex10337a86e19

1113330314777 has 2 divisors, whose sum is σ = 1113330314778. Its totient is φ = 1113330314776.

The previous prime is 1113330314743. The next prime is 1113330314779. The reversal of 1113330314777 is 7774130333111.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1044772223881 + 68558090896 = 1022141^2 + 261836^2 .

It is a cyclic number.

It is not a de Polignac number, because 1113330314777 - 218 = 1113330052633 is a prime.

Together with 1113330314779, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1113330314779) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556665157388 + 556665157389.

It is an arithmetic number, because the mean of its divisors is an integer number (556665157389).

Almost surely, 21113330314777 is an apocalyptic number.

It is an amenable number.

1113330314777 is a deficient number, since it is larger than the sum of its proper divisors (1).

1113330314777 is an equidigital number, since it uses as much as digits as its factorization.

1113330314777 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 111132, while the sum is 41.

Adding to 1113330314777 its reverse (7774130333111), we get a palindrome (8887460647888).

The spelling of 1113330314777 in words is "one trillion, one hundred thirteen billion, three hundred thirty million, three hundred fourteen thousand, seven hundred seventy-seven".