111333122443421 has 2 divisors, whose sum is σ = 111333122443422. Its totient is φ = 111333122443420.

The previous prime is 111333122443369. The next prime is 111333122443423. The reversal of 111333122443421 is 124344221333111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 96141750936100 + 15191371507321 = 9805190^2 + 3897611^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111333122443421 is a prime.

Together with 111333122443423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111333122443423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55666561221710 + 55666561221711.

It is an arithmetic number, because the mean of its divisors is an integer number (55666561221711).

Almost surely, 2^{111333122443421} is an apocalyptic number.

It is an amenable number.

111333122443421 is a deficient number, since it is larger than the sum of its proper divisors (1).

111333122443421 is an equidigital number, since it uses as much as digits as its factorization.

111333122443421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 41472, while the sum is 35.

Adding to 111333122443421 its reverse (124344221333111), we get a palindrome (235677343776532).

The spelling of 111333122443421 in words is "one hundred eleven trillion, three hundred thirty-three billion, one hundred twenty-two million, four hundred forty-three thousand, four hundred twenty-one".