Base | Representation |
---|---|
bin | 10000001100111000111… |
… | …001100011111101011111 |
3 | 10221102202100121010012021 |
4 | 100030320321203331133 |
5 | 121220120343041023 |
6 | 2211244430521011 |
7 | 143302610400322 |
oct | 20147071437537 |
9 | 3842670533167 |
10 | 1113351143263 |
11 | 39a195771597 |
12 | 15b937066167 |
13 | 80cb0b43648 |
14 | 3bc5a71a7b9 |
15 | 1de62b6535d |
hex | 10338e63f5f |
1113351143263 has 2 divisors, whose sum is σ = 1113351143264. Its totient is φ = 1113351143262.
The previous prime is 1113351143239. The next prime is 1113351143273. The reversal of 1113351143263 is 3623411533111.
It is a strong prime.
It is an emirp because it is prime and its reverse (3623411533111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1113351143263 - 29 = 1113351142751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113351143273) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556675571631 + 556675571632.
It is an arithmetic number, because the mean of its divisors is an integer number (556675571632).
Almost surely, 21113351143263 is an apocalyptic number.
1113351143263 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113351143263 is an equidigital number, since it uses as much as digits as its factorization.
1113351143263 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 19440, while the sum is 34.
Adding to 1113351143263 its reverse (3623411533111), we get a palindrome (4736762676374).
The spelling of 1113351143263 in words is "one trillion, one hundred thirteen billion, three hundred fifty-one million, one hundred forty-three thousand, two hundred sixty-three".
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