Base | Representation |
---|---|
bin | 10000001100111100000… |
… | …000100100000101001101 |
3 | 10221102212222202111001221 |
4 | 100030330000210011031 |
5 | 121220222221413123 |
6 | 2211253533003341 |
7 | 143304112662202 |
oct | 20147400440515 |
9 | 3842788674057 |
10 | 1113403310413 |
11 | 39a212162539 |
12 | 15b950623551 |
13 | 80cbb8aa294 |
14 | 3bc63619ca9 |
15 | 1de6751c25d |
hex | 1033c02414d |
1113403310413 has 2 divisors, whose sum is σ = 1113403310414. Its totient is φ = 1113403310412.
The previous prime is 1113403310401. The next prime is 1113403310417. The reversal of 1113403310413 is 3140133043111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1047456043209 + 65947267204 = 1023453^2 + 256802^2 .
It is a cyclic number.
It is not a de Polignac number, because 1113403310413 - 229 = 1112866439501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1113403310417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 556701655206 + 556701655207.
It is an arithmetic number, because the mean of its divisors is an integer number (556701655207).
Almost surely, 21113403310413 is an apocalyptic number.
It is an amenable number.
1113403310413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1113403310413 is an equidigital number, since it uses as much as digits as its factorization.
1113403310413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1113403310413 its reverse (3140133043111), we get a palindrome (4253536353524).
The spelling of 1113403310413 in words is "one trillion, one hundred thirteen billion, four hundred three million, three hundred ten thousand, four hundred thirteen".
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