1113404132020 has 48 divisors (see below), whose sum is σ = 2356258544640. Its totient is φ = 441915035904.

The previous prime is 1113404132003. The next prime is 1113404132041. The reversal of 1113404132020 is 202314043111.

It is a super-2 number, since 2×1113404132020² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1113404131982 and 1113404132000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6177541 + ... + 6355219.

It is an arithmetic number, because the mean of its divisors is an integer number (49088719680).

Almost surely, 2^{1113404132020} is an apocalyptic number.

1113404132020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1113404132020 is an abundant number, since it is smaller than the sum of its proper divisors (1242854412620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1113404132020 is a wasteful number, since it uses less digits than its factorization.

1113404132020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 180112 (or 180110 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 1113404132020 its reverse (202314043111), we get a palindrome (1315718175131).

The spelling of 1113404132020 in words is "one trillion, one hundred thirteen billion, four hundred four million, one hundred thirty-two thousand, twenty".