Base | Representation |
---|---|
bin | 110011110110010010… |
… | …1011111101001100111 |
3 | 101122101201022111211121 |
4 | 1213230211133221213 |
5 | 3311012404344333 |
6 | 123052300114411 |
7 | 11021123401441 |
oct | 1475445375147 |
9 | 348351274747 |
10 | 111343434343 |
11 | 43247514229 |
12 | 196b4835a07 |
13 | a66593197b |
14 | 55637ad491 |
15 | 2d6a01732d |
hex | 19ec95fa67 |
111343434343 has 2 divisors, whose sum is σ = 111343434344. Its totient is φ = 111343434342.
The previous prime is 111343434337. The next prime is 111343434347. The reversal of 111343434343 is 343434343111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111343434343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 111343434299 and 111343434308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111343434347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55671717171 + 55671717172.
It is an arithmetic number, because the mean of its divisors is an integer number (55671717172).
Almost surely, 2111343434343 is an apocalyptic number.
111343434343 is a deficient number, since it is larger than the sum of its proper divisors (1).
111343434343 is an equidigital number, since it uses as much as digits as its factorization.
111343434343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 62208, while the sum is 34.
Adding to 111343434343 its reverse (343434343111), we get a palindrome (454777777454).
The spelling of 111343434343 in words is "one hundred eleven billion, three hundred forty-three million, four hundred thirty-four thousand, three hundred forty-three".
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