111344020213 has 2 divisors, whose sum is σ = 111344020214. Its totient is φ = 111344020212.

The previous prime is 111344020189. The next prime is 111344020231. The reversal of 111344020213 is 312020443111.

Together with next prime (111344020231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 71640269649 + 39703750564 = 267657^2 + 199258^2 .

It is a cyclic number.

It is not a de Polignac number, because 111344020213 - 2²¹ = 111341923061 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111344020013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55672010106 + 55672010107.

It is an arithmetic number, because the mean of its divisors is an integer number (55672010107).

Almost surely, 2^111344020213 is an apocalyptic number.

It is an amenable number.

111344020213 is a deficient number, since it is larger than the sum of its proper divisors (1).

111344020213 is an equidigital number, since it uses as much as digits as its factorization.

111344020213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 111344020213 its reverse (312020443111), we get a palindrome (423364463324).

The spelling of 111344020213 in words is "one hundred eleven billion, three hundred forty-four million, twenty thousand, two hundred thirteen".