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111344020231 is a prime number
BaseRepresentation
bin110011110110010011…
…1101110101100000111
3101122101202102021112011
41213230213232230013
53311013032121411
6123052320435051
711021131361533
oct1475447565407
9348352367464
10111344020231
1143247884434
12196b4a78a87
13a665aa8552
1455638c2bc3
152d6a0d0c21
hex19ec9eeb07

111344020231 has 2 divisors, whose sum is σ = 111344020232. Its totient is φ = 111344020230.

The previous prime is 111344020213. The next prime is 111344020247. The reversal of 111344020231 is 132020443111.

Together with previous prime (111344020213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111344020231 - 211 = 111344018183 is a prime.

It is a super-2 number, since 2×1113440202312 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111344120231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55672010115 + 55672010116.

It is an arithmetic number, because the mean of its divisors is an integer number (55672010116).

Almost surely, 2111344020231 is an apocalyptic number.

111344020231 is a deficient number, since it is larger than the sum of its proper divisors (1).

111344020231 is an equidigital number, since it uses as much as digits as its factorization.

111344020231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 111344020231 its reverse (132020443111), we get a palindrome (243364463342).

The spelling of 111344020231 in words is "one hundred eleven billion, three hundred forty-four million, twenty thousand, two hundred thirty-one".