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11134403302307 is a prime number
BaseRepresentation
bin1010001000000110111000…
…1001110101001110100011
31110102102211201011212010212
42202001232021311032203
52424411224221133212
635403024012444335
72226301615331615
oct242015611651643
943372751155125
1011134403302307
11360308a43325a
1212b9b091796ab
13629c7b6469bc
142a6c9d778db5
15144970da9e22
hexa206e2753a3

11134403302307 has 2 divisors, whose sum is σ = 11134403302308. Its totient is φ = 11134403302306.

The previous prime is 11134403302259. The next prime is 11134403302339. The reversal of 11134403302307 is 70320330443111.

It is an a-pointer prime, because the next prime (11134403302339) can be obtained adding 11134403302307 to its sum of digits (32).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11134403302307 - 236 = 11065683825571 is a prime.

It is not a weakly prime, because it can be changed into another prime (11134403302357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567201651153 + 5567201651154.

It is an arithmetic number, because the mean of its divisors is an integer number (5567201651154).

Almost surely, 211134403302307 is an apocalyptic number.

11134403302307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11134403302307 is an equidigital number, since it uses as much as digits as its factorization.

11134403302307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18144, while the sum is 32.

Adding to 11134403302307 its reverse (70320330443111), we get a palindrome (81454733745418).

The spelling of 11134403302307 in words is "eleven trillion, one hundred thirty-four billion, four hundred three million, three hundred two thousand, three hundred seven".