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11135205524447 is a prime number
BaseRepresentation
bin1010001000001001110111…
…1110000100001111011111
31110102111220121200222000222
42202002131332010033133
52424414400103240242
635403235351111555
72226330526161644
oct242023576041737
943374817628028
1011135205524447
113603461251664
1212ba0b19725bb
1362a0788c7164
142a6d38121dcb
151449bb5205d2
hexa209df843df

11135205524447 has 2 divisors, whose sum is σ = 11135205524448. Its totient is φ = 11135205524446.

The previous prime is 11135205524437. The next prime is 11135205524453. The reversal of 11135205524447 is 74442550253111.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11135205524447 - 24 = 11135205524431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11135205524398 and 11135205524407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11135205524437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5567602762223 + 5567602762224.

It is an arithmetic number, because the mean of its divisors is an integer number (5567602762224).

Almost surely, 211135205524447 is an apocalyptic number.

11135205524447 is a deficient number, since it is larger than the sum of its proper divisors (1).

11135205524447 is an equidigital number, since it uses as much as digits as its factorization.

11135205524447 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672000, while the sum is 44.

Adding to 11135205524447 its reverse (74442550253111), we get a palindrome (85577755777558).

The spelling of 11135205524447 in words is "eleven trillion, one hundred thirty-five billion, two hundred five million, five hundred twenty-four thousand, four hundred forty-seven".