111400324130111 has 2 divisors, whose sum is σ = 111400324130112. Its totient is φ = 111400324130110.

The previous prime is 111400324130093. The next prime is 111400324130113. The reversal of 111400324130111 is 111031423004111.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111400324130111 is a prime.

It is a super-2 number, since 2×111400324130111² (a number of 29 digits) contains 22 as substring.

Together with 111400324130113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111400324130113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55700162065055 + 55700162065056.

It is an arithmetic number, because the mean of its divisors is an integer number (55700162065056).

Almost surely, 2^{111400324130111} is an apocalyptic number.

111400324130111 is a deficient number, since it is larger than the sum of its proper divisors (1).

111400324130111 is an equidigital number, since it uses as much as digits as its factorization.

111400324130111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 111400324130111 its reverse (111031423004111), we get a palindrome (222431747134222).

The spelling of 111400324130111 in words is "one hundred eleven trillion, four hundred billion, three hundred twenty-four million, one hundred thirty thousand, one hundred eleven".