11140034038037 has 2 divisors, whose sum is σ = 11140034038038. Its totient is φ = 11140034038036.

The previous prime is 11140034037997. The next prime is 11140034038039. The reversal of 11140034038037 is 73083043004111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9180815160196 + 1959218877841 = 3029986^2 + 1399721^2 .

It is a cyclic number.

It is not a de Polignac number, because 11140034038037 - 2⁶ = 11140034037973 is a prime.

Together with 11140034038039, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11140034037988 and 11140034038006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11140034038039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570017019018 + 5570017019019.

It is an arithmetic number, because the mean of its divisors is an integer number (5570017019019).

Almost surely, 2^{11140034038037} is an apocalyptic number.

It is an amenable number.

11140034038037 is a deficient number, since it is larger than the sum of its proper divisors (1).

11140034038037 is an equidigital number, since it uses as much as digits as its factorization.

11140034038037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24192, while the sum is 35.

The spelling of 11140034038037 in words is "eleven trillion, one hundred forty billion, thirty-four million, thirty-eight thousand, thirty-seven".