111402221241413 has 2 divisors, whose sum is σ = 111402221241414. Its totient is φ = 111402221241412.

The previous prime is 111402221241341. The next prime is 111402221241449. The reversal of 111402221241413 is 314142122204111.

It is a happy number.

Together with previous prime (111402221241341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 56395924517284 + 55006296724129 = 7509722^2 + 7416623^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111402221241413 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111402221241713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55701110620706 + 55701110620707.

It is an arithmetic number, because the mean of its divisors is an integer number (55701110620707).

Almost surely, 2^{111402221241413} is an apocalyptic number.

It is an amenable number.

111402221241413 is a deficient number, since it is larger than the sum of its proper divisors (1).

111402221241413 is an equidigital number, since it uses as much as digits as its factorization.

111402221241413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 29.

Adding to 111402221241413 its reverse (314142122204111), we get a palindrome (425544343445524).

The spelling of 111402221241413 in words is "one hundred eleven trillion, four hundred two billion, two hundred twenty-one million, two hundred forty-one thousand, four hundred thirteen".