Base | Representation |
---|---|
bin | 10100110000000010… |
… | …11000011001011101 |
3 | 1001202101200122210012 |
4 | 22120001120121131 |
5 | 140303422333001 |
6 | 5041242053005 |
7 | 543033056651 |
oct | 123001303135 |
9 | 31671618705 |
10 | 11140433501 |
11 | 47a753663a |
12 | 21aaaaa165 |
13 | 10870570b2 |
14 | 7797c8a61 |
15 | 45307e2bb |
hex | 29805865d |
11140433501 has 2 divisors, whose sum is σ = 11140433502. Its totient is φ = 11140433500.
The previous prime is 11140433471. The next prime is 11140433543. The reversal of 11140433501 is 10533404111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10789807876 + 350625625 = 103874^2 + 18725^2 .
It is a cyclic number.
It is not a de Polignac number, because 11140433501 - 210 = 11140432477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11140438501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570216750 + 5570216751.
It is an arithmetic number, because the mean of its divisors is an integer number (5570216751).
Almost surely, 211140433501 is an apocalyptic number.
It is an amenable number.
11140433501 is a deficient number, since it is larger than the sum of its proper divisors (1).
11140433501 is an equidigital number, since it uses as much as digits as its factorization.
11140433501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 11140433501 its reverse (10533404111), we get a palindrome (21673837612).
The spelling of 11140433501 in words is "eleven billion, one hundred forty million, four hundred thirty-three thousand, five hundred one".
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