Base | Representation |
---|---|
bin | 10100110000001000… |
… | …00011101011001101 |
3 | 1001202110000022010121 |
4 | 22120010003223031 |
5 | 140304112310203 |
6 | 5041305104541 |
7 | 543042041206 |
oct | 123004035315 |
9 | 31673008117 |
10 | 11141135053 |
11 | 47a7975734 |
12 | 21ab188151 |
13 | 1087241509 |
14 | 77992c5ad |
15 | 45316c0bd |
hex | 298103acd |
11141135053 has 2 divisors, whose sum is σ = 11141135054. Its totient is φ = 11141135052.
The previous prime is 11141135039. The next prime is 11141135063. The reversal of 11141135053 is 35053114111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9896668324 + 1244466729 = 99482^2 + 35277^2 .
It is an emirp because it is prime and its reverse (35053114111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11141135053 - 29 = 11141134541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11141135003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570567526 + 5570567527.
It is an arithmetic number, because the mean of its divisors is an integer number (5570567527).
Almost surely, 211141135053 is an apocalyptic number.
It is an amenable number.
11141135053 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141135053 is an equidigital number, since it uses as much as digits as its factorization.
11141135053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 11141135053 its reverse (35053114111), we get a palindrome (46194249164).
The spelling of 11141135053 in words is "eleven billion, one hundred forty-one million, one hundred thirty-five thousand, fifty-three".
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