1114121104001 has 2 divisors, whose sum is σ = 1114121104002. Its totient is φ = 1114121104000.

The previous prime is 1114121103971. The next prime is 1114121104003. The reversal of 1114121104001 is 1004011214111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 820747214401 + 293373889600 = 905951^2 + 541640^2 .

It is a cyclic number.

It is not a de Polignac number, because 1114121104001 - 2¹⁴ = 1114121087617 is a prime.

Together with 1114121104003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1114121104003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557060552000 + 557060552001.

It is an arithmetic number, because the mean of its divisors is an integer number (557060552001).

Almost surely, 2^{1114121104001} is an apocalyptic number.

It is an amenable number.

1114121104001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114121104001 is an equidigital number, since it uses as much as digits as its factorization.

1114121104001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 1114121104001 its reverse (1004011214111), we get a palindrome (2118132318112).

The spelling of 1114121104001 in words is "one trillion, one hundred fourteen billion, one hundred twenty-one million, one hundred four thousand, one".