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1114124344481 is a prime number
BaseRepresentation
bin10000001101100110111…
…111000101110010100001
310221111202020111210212102
4100031212333011302201
5121223211313010411
62211453251140145
7143331016450301
oct20154677056241
93844666453772
101114124344481
1139a552169065
1215bb11ba4655
13810a50a2665
143bcd12ab601
151deaa996d3b
hex10366fc5ca1

1114124344481 has 2 divisors, whose sum is σ = 1114124344482. Its totient is φ = 1114124344480.

The previous prime is 1114124344439. The next prime is 1114124344483. The reversal of 1114124344481 is 1844434214111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 988354105600 + 125770238881 = 994160^2 + 354641^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1114124344481 is a prime.

It is a super-2 number, since 2×11141243444812 (a number of 25 digits) contains 22 as substring.

Together with 1114124344483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1114124344483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557062172240 + 557062172241.

It is an arithmetic number, because the mean of its divisors is an integer number (557062172241).

Almost surely, 21114124344481 is an apocalyptic number.

It is an amenable number.

1114124344481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114124344481 is an equidigital number, since it uses as much as digits as its factorization.

1114124344481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 49152, while the sum is 38.

Adding to 1114124344481 its reverse (1844434214111), we get a palindrome (2958558558592).

The spelling of 1114124344481 in words is "one trillion, one hundred fourteen billion, one hundred twenty-four million, three hundred forty-four thousand, four hundred eighty-one".