Base | Representation |
---|---|
bin | 1010001000100000101111… |
… | …0100010100111010001010 |
3 | 1110110002202101020222202120 |
4 | 2202020023310110322022 |
5 | 2430014432404313310 |
6 | 35410132411512110 |
7 | 2226635606425056 |
oct | 242101364247212 |
9 | 43402671228676 |
10 | 11141343432330 |
11 | 3606020a05701 |
12 | 12bb325458636 |
13 | 62a816419c07 |
14 | 2a735b38cc66 |
15 | 144c2a2e9b70 |
hex | a220bd14e8a |
11141343432330 has 32 divisors (see below), whose sum is σ = 26739748689984. Its totient is φ = 2970966642816.
The previous prime is 11141343432311. The next prime is 11141343432367. The reversal of 11141343432330 is 3323434314111.
It is a junction number, because it is equal to n+sod(n) for n = 11141343432291 and 11141343432300.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2075947 + ... + 5156766.
It is an arithmetic number, because the mean of its divisors is an integer number (835617146562).
Almost surely, 211141343432330 is an apocalyptic number.
11141343432330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11141343432330 is an abundant number, since it is smaller than the sum of its proper divisors (15598405257654).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11141343432330 is a wasteful number, since it uses less digits than its factorization.
11141343432330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7284070.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 11141343432330 its reverse (3323434314111), we get a palindrome (14464777746441).
The spelling of 11141343432330 in words is "eleven trillion, one hundred forty-one billion, three hundred forty-three million, four hundred thirty-two thousand, three hundred thirty".
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