Base | Representation |
---|---|
bin | 1010001000100001000100… |
… | …0011101011000001101011 |
3 | 1110110002222111200020000021 |
4 | 2202020101003223001223 |
5 | 2430020122410404123 |
6 | 35410145232021311 |
7 | 2226641024561044 |
oct | 242102103530153 |
9 | 43402874606007 |
10 | 11141431341163 |
11 | 3606066598932 |
12 | 12bb34a991837 |
13 | 62a82b6b9086 |
14 | 2a7368d138cb |
15 | 144c32db1c5d |
hex | a22110eb06b |
11141431341163 has 2 divisors, whose sum is σ = 11141431341164. Its totient is φ = 11141431341162.
The previous prime is 11141431341151. The next prime is 11141431341319. The reversal of 11141431341163 is 36114313414111.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11141431341163 is a prime.
It is not a weakly prime, because it can be changed into another prime (11141431341113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5570715670581 + 5570715670582.
It is an arithmetic number, because the mean of its divisors is an integer number (5570715670582).
Almost surely, 211141431341163 is an apocalyptic number.
11141431341163 is a deficient number, since it is larger than the sum of its proper divisors (1).
11141431341163 is an equidigital number, since it uses as much as digits as its factorization.
11141431341163 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10368, while the sum is 34.
Adding to 11141431341163 its reverse (36114313414111), we get a palindrome (47255744755274).
The spelling of 11141431341163 in words is "eleven trillion, one hundred forty-one billion, four hundred thirty-one million, three hundred forty-one thousand, one hundred sixty-three".
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