Base | Representation |
---|---|
bin | 10000001101101000010… |
… | …011110011001011000111 |
3 | 10221111210210021222202111 |
4 | 100031220103303023013 |
5 | 121223233004103341 |
6 | 2211455403121451 |
7 | 143331406264633 |
oct | 20155023631307 |
9 | 3844723258674 |
10 | 1114146550471 |
11 | 39a563755819 |
12 | 15bb19513287 |
13 | 810a9878bb6 |
14 | 3bcd420bdc3 |
15 | 1deac8d1681 |
hex | 103684f32c7 |
1114146550471 has 2 divisors, whose sum is σ = 1114146550472. Its totient is φ = 1114146550470.
The previous prime is 1114146550457. The next prime is 1114146550499. The reversal of 1114146550471 is 1740556414111.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1114146550471 - 213 = 1114146542279 is a prime.
It is a super-3 number, since 3×11141465504713 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1114146550271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557073275235 + 557073275236.
It is an arithmetic number, because the mean of its divisors is an integer number (557073275236).
Almost surely, 21114146550471 is an apocalyptic number.
1114146550471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114146550471 is an equidigital number, since it uses as much as digits as its factorization.
1114146550471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 40.
The spelling of 1114146550471 in words is "one trillion, one hundred fourteen billion, one hundred forty-six million, five hundred fifty thousand, four hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •