111421241014003 has 2 divisors, whose sum is σ = 111421241014004. Its totient is φ = 111421241014002.

The previous prime is 111421241013997. The next prime is 111421241014009. The reversal of 111421241014003 is 300410142124111.

It is a balanced prime because it is at equal distance from previous prime (111421241013997) and next prime (111421241014009).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-111421241014003 is a prime.

It is not a weakly prime, because it can be changed into another prime (111421241014009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55710620507001 + 55710620507002.

It is an arithmetic number, because the mean of its divisors is an integer number (55710620507002).

Almost surely, 2^{111421241014003} is an apocalyptic number.

111421241014003 is a deficient number, since it is larger than the sum of its proper divisors (1).

111421241014003 is an equidigital number, since it uses as much as digits as its factorization.

111421241014003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 111421241014003 its reverse (300410142124111), we get a palindrome (411831383138114).

The spelling of 111421241014003 in words is "one hundred eleven trillion, four hundred twenty-one billion, two hundred forty-one million, fourteen thousand, three".