Base | Representation |
---|---|
bin | 10100110000010001… |
… | …00011010011110111 |
3 | 1001202112020011020221 |
4 | 22120020203103313 |
5 | 140304413010312 |
6 | 5041350235211 |
7 | 543055046104 |
oct | 123010432367 |
9 | 31675204227 |
10 | 11142313207 |
11 | 47a85aa913 |
12 | 21ab655b07 |
13 | 108756484c |
14 | 779b57aab |
15 | 453301207 |
hex | 2982234f7 |
11142313207 has 2 divisors, whose sum is σ = 11142313208. Its totient is φ = 11142313206.
The previous prime is 11142313157. The next prime is 11142313243. The reversal of 11142313207 is 70231324111.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11142313207 is a prime.
It is a super-2 number, since 2×111423132072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11142313277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571156603 + 5571156604.
It is an arithmetic number, because the mean of its divisors is an integer number (5571156604).
Almost surely, 211142313207 is an apocalyptic number.
11142313207 is a deficient number, since it is larger than the sum of its proper divisors (1).
11142313207 is an equidigital number, since it uses as much as digits as its factorization.
11142313207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 11142313207 its reverse (70231324111), we get a palindrome (81373637318).
The spelling of 11142313207 in words is "eleven billion, one hundred forty-two million, three hundred thirteen thousand, two hundred seven".
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