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11142453103 is a prime number
BaseRepresentation
bin10100110000010010…
…00101011101101111
31001202112111021011021
422120021011131233
5140304431444403
65041353235011
7543056201005
oct123011053557
931675437137
1011142453103
1147a8695a31
1221ab702a67
1310875b3422
14779b92a75
1545332c8bd
hex29824576f

11142453103 has 2 divisors, whose sum is σ = 11142453104. Its totient is φ = 11142453102.

The previous prime is 11142453067. The next prime is 11142453107. The reversal of 11142453103 is 30135424111.

11142453103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11142453103 - 229 = 10605582191 is a prime.

It is a super-2 number, since 2×111424531032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11142453107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571226551 + 5571226552.

It is an arithmetic number, because the mean of its divisors is an integer number (5571226552).

Almost surely, 211142453103 is an apocalyptic number.

11142453103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11142453103 is an equidigital number, since it uses as much as digits as its factorization.

11142453103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11142453103 its reverse (30135424111), we get a palindrome (41277877214).

The spelling of 11142453103 in words is "eleven billion, one hundred forty-two million, four hundred fifty-three thousand, one hundred three".