Search a number
-
+
111430520412017 is a prime number
BaseRepresentation
bin11001010101100001110000…
…100101100001011101110001
3112121112122122120002011001012
4121111201300211201131301
5104101134201211141032
61032554250244520305
732320406113425632
oct3125416045413561
9477478576064035
10111430520412017
113256146686a794
12105b7b939b0095
134a23b12021311
141d733a1b41889
15cd386bee76b2
hex655870961771

111430520412017 has 2 divisors, whose sum is σ = 111430520412018. Its totient is φ = 111430520412016.

The previous prime is 111430520411983. The next prime is 111430520412019. The reversal of 111430520412017 is 710214025034111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111427531493776 + 2988918241 = 10555924^2 + 54671^2 .

It is a cyclic number.

It is not a de Polignac number, because 111430520412017 - 214 = 111430520395633 is a prime.

Together with 111430520412019, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (111430520412019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55715260206008 + 55715260206009.

It is an arithmetic number, because the mean of its divisors is an integer number (55715260206009).

Almost surely, 2111430520412017 is an apocalyptic number.

It is an amenable number.

111430520412017 is a deficient number, since it is larger than the sum of its proper divisors (1).

111430520412017 is an equidigital number, since it uses as much as digits as its factorization.

111430520412017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 32.

Adding to 111430520412017 its reverse (710214025034111), we get a palindrome (821644545446128).

The spelling of 111430520412017 in words is "one hundred eleven trillion, four hundred thirty billion, five hundred twenty million, four hundred twelve thousand, seventeen".