Base | Representation |
---|---|
bin | 10000001101110010010… |
… | …000000001110100100101 |
3 | 10221112020102010110211012 |
4 | 100031302100001310211 |
5 | 121224103203142203 |
6 | 2211524121552005 |
7 | 143335503026303 |
oct | 20156220016445 |
9 | 3845212113735 |
10 | 1114313334053 |
11 | 39a639910797 |
12 | 15bb65345605 |
13 | 811052a31ca |
14 | 3bd0c425273 |
15 | 1debc378bd8 |
hex | 10372401d25 |
1114313334053 has 2 divisors, whose sum is σ = 1114313334054. Its totient is φ = 1114313334052.
The previous prime is 1114313334037. The next prime is 1114313334151. The reversal of 1114313334053 is 3504333134111.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 778518581569 + 335794752484 = 882337^2 + 579478^2 .
It is a cyclic number.
It is not a de Polignac number, because 1114313334053 - 24 = 1114313334037 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1114313334353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557156667026 + 557156667027.
It is an arithmetic number, because the mean of its divisors is an integer number (557156667027).
Almost surely, 21114313334053 is an apocalyptic number.
It is an amenable number.
1114313334053 is a deficient number, since it is larger than the sum of its proper divisors (1).
1114313334053 is an equidigital number, since it uses as much as digits as its factorization.
1114313334053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 32.
Adding to 1114313334053 its reverse (3504333134111), we get a palindrome (4618646468164).
The spelling of 1114313334053 in words is "one trillion, one hundred fourteen billion, three hundred thirteen million, three hundred thirty-four thousand, fifty-three".
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