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111432303149953 is a prime number
BaseRepresentation
bin11001010101100011011010…
…110110001000001110000001
3112121112211020210121121202011
4121111203122312020032001
5104101201324101244303
61032555143211052521
732320501231436422
oct3125433266101601
9477484223547664
10111432303149953
11325621a1104125
12105b83b0a41141
134a24037479236
141d734d0803649
15cd392379116d
hex6558dad88381

111432303149953 has 2 divisors, whose sum is σ = 111432303149954. Its totient is φ = 111432303149952.

The previous prime is 111432303149887. The next prime is 111432303150053. The reversal of 111432303149953 is 359941303234111.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 60576692308609 + 50855610841344 = 7783103^2 + 7131312^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111432303149953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 111432303149897 and 111432303149906.

It is not a weakly prime, because it can be changed into another prime (111432303141953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55716151574976 + 55716151574977.

It is an arithmetic number, because the mean of its divisors is an integer number (55716151574977).

Almost surely, 2111432303149953 is an apocalyptic number.

It is an amenable number.

111432303149953 is a deficient number, since it is larger than the sum of its proper divisors (1).

111432303149953 is an equidigital number, since it uses as much as digits as its factorization.

111432303149953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1049760, while the sum is 49.

The spelling of 111432303149953 in words is "one hundred eleven trillion, four hundred thirty-two billion, three hundred three million, one hundred forty-nine thousand, nine hundred fifty-three".