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111432303150053 is a prime number
BaseRepresentation
bin11001010101100011011010…
…110110001000001111100101
3112121112211020210121121212212
4121111203122312020033211
5104101201324101300203
61032555143211053205
732320501231436624
oct3125433266101745
9477484223547785
10111432303150053
11325621a1104206
12105b83b0a41205
134a240374792b2
141d734d08036bb
15cd39237911d8
hex6558dad883e5

111432303150053 has 2 divisors, whose sum is σ = 111432303150054. Its totient is φ = 111432303150052.

The previous prime is 111432303149953. The next prime is 111432303150109. The reversal of 111432303150053 is 350051303234111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 89149060166884 + 22283242983169 = 9441878^2 + 4720513^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-111432303150053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111432303150353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55716151575026 + 55716151575027.

It is an arithmetic number, because the mean of its divisors is an integer number (55716151575027).

Almost surely, 2111432303150053 is an apocalyptic number.

It is an amenable number.

111432303150053 is a deficient number, since it is larger than the sum of its proper divisors (1).

111432303150053 is an equidigital number, since it uses as much as digits as its factorization.

111432303150053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16200, while the sum is 32.

Adding to 111432303150053 its reverse (350051303234111), we get a palindrome (461483606384164).

The spelling of 111432303150053 in words is "one hundred eleven trillion, four hundred thirty-two billion, three hundred three million, one hundred fifty thousand, fifty-three".