Base | Representation |
---|---|
bin | 11001010101100011011010… |
… | …110110001000001111100101 |
3 | 112121112211020210121121212212 |
4 | 121111203122312020033211 |
5 | 104101201324101300203 |
6 | 1032555143211053205 |
7 | 32320501231436624 |
oct | 3125433266101745 |
9 | 477484223547785 |
10 | 111432303150053 |
11 | 325621a1104206 |
12 | 105b83b0a41205 |
13 | 4a240374792b2 |
14 | 1d734d08036bb |
15 | cd39237911d8 |
hex | 6558dad883e5 |
111432303150053 has 2 divisors, whose sum is σ = 111432303150054. Its totient is φ = 111432303150052.
The previous prime is 111432303149953. The next prime is 111432303150109. The reversal of 111432303150053 is 350051303234111.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 89149060166884 + 22283242983169 = 9441878^2 + 4720513^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111432303150053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (111432303150353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55716151575026 + 55716151575027.
It is an arithmetic number, because the mean of its divisors is an integer number (55716151575027).
Almost surely, 2111432303150053 is an apocalyptic number.
It is an amenable number.
111432303150053 is a deficient number, since it is larger than the sum of its proper divisors (1).
111432303150053 is an equidigital number, since it uses as much as digits as its factorization.
111432303150053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 32.
Adding to 111432303150053 its reverse (350051303234111), we get a palindrome (461483606384164).
The spelling of 111432303150053 in words is "one hundred eleven trillion, four hundred thirty-two billion, three hundred three million, one hundred fifty thousand, fifty-three".
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