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1114333310113 is a prime number
BaseRepresentation
bin10000001101110011011…
…100001110110010100001
310221112021210201100211021
4100031303130032302201
5121224123311410423
62211530114045441
7143336134565452
oct20156334166241
93845253640737
101114333310113
1139a64a115031
1215bb6bb79881
138110947876a
143bd10d45129
151debdec295d
hex1037370eca1

1114333310113 has 2 divisors, whose sum is σ = 1114333310114. Its totient is φ = 1114333310112.

The previous prime is 1114333310087. The next prime is 1114333310117. The reversal of 1114333310113 is 3110133334111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1059186772224 + 55146537889 = 1029168^2 + 234833^2 .

It is an emirp because it is prime and its reverse (3110133334111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114333310113 - 25 = 1114333310081 is a prime.

It is not a weakly prime, because it can be changed into another prime (1114333310117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557166655056 + 557166655057.

It is an arithmetic number, because the mean of its divisors is an integer number (557166655057).

Almost surely, 21114333310113 is an apocalyptic number.

It is an amenable number.

1114333310113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114333310113 is an equidigital number, since it uses as much as digits as its factorization.

1114333310113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 1114333310113 its reverse (3110133334111), we get a palindrome (4224466644224).

The spelling of 1114333310113 in words is "one trillion, one hundred fourteen billion, three hundred thirty-three million, three hundred ten thousand, one hundred thirteen".