1114412221231 has 2 divisors, whose sum is σ = 1114412221232. Its totient is φ = 1114412221230.

The previous prime is 1114412221193. The next prime is 1114412221253. The reversal of 1114412221231 is 1321222144111.

It is a strong prime.

It is an emirp because it is prime and its reverse (1321222144111) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1114412221231 - 2³¹ = 1112264737583 is a prime.

It is a super-2 number, since 2×1114412221231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1114412221196 and 1114412221205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1114412221031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 557206110615 + 557206110616.

It is an arithmetic number, because the mean of its divisors is an integer number (557206110616).

Almost surely, 2^{1114412221231} is an apocalyptic number.

1114412221231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1114412221231 is an equidigital number, since it uses as much as digits as its factorization.

1114412221231 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 768, while the sum is 25.

Adding to 1114412221231 its reverse (1321222144111), we get a palindrome (2435634365342).

The spelling of 1114412221231 in words is "one trillion, one hundred fourteen billion, four hundred twelve million, two hundred twenty-one thousand, two hundred thirty-one".