Base | Representation |
---|---|
bin | 10100110000100001… |
… | …00111000001101111 |
3 | 1001202200012110220002 |
4 | 22120100213001233 |
5 | 140310433104313 |
6 | 5041503414515 |
7 | 543112024454 |
oct | 123020470157 |
9 | 31680173802 |
10 | 11144425583 |
11 | 47a9812985 |
12 | 21b02b443b |
13 | 1087b24185 |
14 | 77a14782b |
15 | 4535bc058 |
hex | 29842706f |
11144425583 has 2 divisors, whose sum is σ = 11144425584. Its totient is φ = 11144425582.
The previous prime is 11144425577. The next prime is 11144425609. The reversal of 11144425583 is 38552444111.
It is a weak prime.
It is an emirp because it is prime and its reverse (38552444111) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11144425583 - 230 = 10070683759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11144425553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5572212791 + 5572212792.
It is an arithmetic number, because the mean of its divisors is an integer number (5572212792).
Almost surely, 211144425583 is an apocalyptic number.
11144425583 is a deficient number, since it is larger than the sum of its proper divisors (1).
11144425583 is an equidigital number, since it uses as much as digits as its factorization.
11144425583 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 76800, while the sum is 38.
Adding to 11144425583 its reverse (38552444111), we get a palindrome (49696869694).
The spelling of 11144425583 in words is "eleven billion, one hundred forty-four million, four hundred twenty-five thousand, five hundred eighty-three".
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