Base | Representation |
---|---|
bin | 110011111001100011… |
… | …1100000000100010001 |
3 | 101122200100111122110021 |
4 | 1213303013200010101 |
5 | 3311223432342431 |
6 | 123111212503441 |
7 | 11023623654514 |
oct | 1476307400421 |
9 | 348610448407 |
10 | 111453012241 |
11 | 432a335777a |
12 | 1972547ab81 |
13 | a682549b6c |
14 | 5574174d7b |
15 | 2d7495eb11 |
hex | 19f31e0111 |
111453012241 has 2 divisors, whose sum is σ = 111453012242. Its totient is φ = 111453012240.
The previous prime is 111453012233. The next prime is 111453012263. The reversal of 111453012241 is 142210354111.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 100280522241 + 11172490000 = 316671^2 + 105700^2 .
It is a cyclic number.
It is not a de Polignac number, because 111453012241 - 23 = 111453012233 is a prime.
It is a super-3 number, since 3×1114530122413 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (111453012211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55726506120 + 55726506121.
It is an arithmetic number, because the mean of its divisors is an integer number (55726506121).
Almost surely, 2111453012241 is an apocalyptic number.
It is an amenable number.
111453012241 is a deficient number, since it is larger than the sum of its proper divisors (1).
111453012241 is an equidigital number, since it uses as much as digits as its factorization.
111453012241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 111453012241 its reverse (142210354111), we get a palindrome (253663366352).
The spelling of 111453012241 in words is "one hundred eleven billion, four hundred fifty-three million, twelve thousand, two hundred forty-one".
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