111477804353983 has 2 divisors, whose sum is σ = 111477804353984. Its totient is φ = 111477804353982.

The previous prime is 111477804353893. The next prime is 111477804354013. The reversal of 111477804353983 is 389353408774111.

Together with previous prime (111477804353893) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 111477804353983 - 2²¹ = 111477802256831 is a prime.

It is a super-2 number, since 2×111477804353983² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (111477804353483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55738902176991 + 55738902176992.

It is an arithmetic number, because the mean of its divisors is an integer number (55738902176992).

Almost surely, 2^{111477804353983} is an apocalyptic number.

111477804353983 is a deficient number, since it is larger than the sum of its proper divisors (1).

111477804353983 is an equidigital number, since it uses as much as digits as its factorization.

111477804353983 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60963840, while the sum is 64.

The spelling of 111477804353983 in words is "one hundred eleven trillion, four hundred seventy-seven billion, eight hundred four million, three hundred fifty-three thousand, nine hundred eighty-three".