Base | Representation |
---|---|
bin | 10100110001001100… |
… | …01010111100000111 |
3 | 1001210001211122010212 |
4 | 22120212022330013 |
5 | 140313404441303 |
6 | 5042224510035 |
7 | 543211045112 |
oct | 123046127407 |
9 | 31701748125 |
10 | 11150077703 |
11 | 4801a23456 |
12 | 21b217b31b |
13 | 1089052a1b |
14 | 77abb9579 |
15 | 453d36ad8 |
hex | 29898af07 |
11150077703 has 2 divisors, whose sum is σ = 11150077704. Its totient is φ = 11150077702.
The previous prime is 11150077693. The next prime is 11150077733. The reversal of 11150077703 is 30777005111.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11150077703 - 214 = 11150061319 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11150077703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11150077733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5575038851 + 5575038852.
It is an arithmetic number, because the mean of its divisors is an integer number (5575038852).
Almost surely, 211150077703 is an apocalyptic number.
11150077703 is a deficient number, since it is larger than the sum of its proper divisors (1).
11150077703 is an equidigital number, since it uses as much as digits as its factorization.
11150077703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5145, while the sum is 32.
The spelling of 11150077703 in words is "eleven billion, one hundred fifty million, seventy-seven thousand, seven hundred three".
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