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11167883084773 is a prime number
BaseRepresentation
bin1010001010000011100110…
…1101000100001111100101
31110112122020222022000200001
42202200321231010033211
52430433311032203043
635430242112421301
72231565360644062
oct242407155041745
943478228260601
1011167883084773
1136162aa945368
1213044b1547831
13630185919c7c
142a8757ddbc69
1514578024a74d
hexa2839b443e5

11167883084773 has 2 divisors, whose sum is σ = 11167883084774. Its totient is φ = 11167883084772.

The previous prime is 11167883084759. The next prime is 11167883084777. The reversal of 11167883084773 is 37748038876111.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9599382334369 + 1568500750404 = 3098287^2 + 1252398^2 .

It is a cyclic number.

It is not a de Polignac number, because 11167883084773 - 25 = 11167883084741 is a prime.

It is a super-2 number, since 2×111678830847732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11167883084777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5583941542386 + 5583941542387.

It is an arithmetic number, because the mean of its divisors is an integer number (5583941542387).

Almost surely, 211167883084773 is an apocalyptic number.

It is an amenable number.

11167883084773 is a deficient number, since it is larger than the sum of its proper divisors (1).

11167883084773 is an equidigital number, since it uses as much as digits as its factorization.

11167883084773 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37933056, while the sum is 64.

The spelling of 11167883084773 in words is "eleven trillion, one hundred sixty-seven billion, eight hundred eighty-three million, eighty-four thousand, seven hundred seventy-three".