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11172113568013 is a prime number
BaseRepresentation
bin1010001010010011010111…
…0111000101000100001101
31110120001011210200211200111
42202210311313011010031
52431020442033134023
635432221554400021
72232105250315336
oct242446567050415
943501153624614
1011172113568013
113618080942002
121305292290011
136306ab2098a8
142a8a39bcb28d
1514592b84c00d
hexa2935dc510d

11172113568013 has 2 divisors, whose sum is σ = 11172113568014. Its totient is φ = 11172113568012.

The previous prime is 11172113567983. The next prime is 11172113568053. The reversal of 11172113568013 is 31086531127111.

It is an a-pointer prime, because the next prime (11172113568053) can be obtained adding 11172113568013 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5908195539684 + 5263918028329 = 2430678^2 + 2294323^2 .

It is a cyclic number.

It is not a de Polignac number, because 11172113568013 - 225 = 11172080013581 is a prime.

It is a super-2 number, since 2×111721135680132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11172113568053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5586056784006 + 5586056784007.

It is an arithmetic number, because the mean of its divisors is an integer number (5586056784007).

Almost surely, 211172113568013 is an apocalyptic number.

It is an amenable number.

11172113568013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11172113568013 is an equidigital number, since it uses as much as digits as its factorization.

11172113568013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30240, while the sum is 40.

The spelling of 11172113568013 in words is "eleven trillion, one hundred seventy-two billion, one hundred thirteen million, five hundred sixty-eight thousand, thirteen".