Base | Representation |
---|---|
bin | 10000010010110010011… |
… | …000110101000011111001 |
3 | 10222001002201122100212012 |
4 | 100102302120311003321 |
5 | 121321103143201301 |
6 | 2214213105255305 |
7 | 143615551641434 |
oct | 20226230650371 |
9 | 3861081570765 |
10 | 1119684350201 |
11 | 3a194569770a |
12 | 161004034535 |
13 | 8177cc65a81 |
14 | 3c29b8a481b |
15 | 1e1d3b6aebb |
hex | 104b26350f9 |
1119684350201 has 2 divisors, whose sum is σ = 1119684350202. Its totient is φ = 1119684350200.
The previous prime is 1119684350171. The next prime is 1119684350203. The reversal of 1119684350201 is 1020534869111.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 923182758976 + 196501591225 = 960824^2 + 443285^2 .
It is a cyclic number.
It is not a de Polignac number, because 1119684350201 - 222 = 1119680155897 is a prime.
Together with 1119684350203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1119684350203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 559842175100 + 559842175101.
It is an arithmetic number, because the mean of its divisors is an integer number (559842175101).
Almost surely, 21119684350201 is an apocalyptic number.
It is an amenable number.
1119684350201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1119684350201 is an equidigital number, since it uses as much as digits as its factorization.
1119684350201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 41.
The spelling of 1119684350201 in words is "one trillion, one hundred nineteen billion, six hundred eighty-four million, three hundred fifty thousand, two hundred one".
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