Base | Representation |
---|---|
bin | 11001011101110101001011… |
… | …000010000100000100111111 |
3 | 112200120012110200202211200102 |
4 | 121131311023002010010333 |
5 | 104140011243434304413 |
6 | 1034112334335551315 |
7 | 32406546121454402 |
oct | 3135651302040477 |
9 | 480505420684612 |
10 | 112001121009983 |
11 | 32761454a46407 |
12 | 1068a69898b53b |
13 | 4a65877b6153a |
14 | 1d92c5163bd39 |
15 | ce3615d26458 |
hex | 65dd4b08413f |
112001121009983 has 2 divisors, whose sum is σ = 112001121009984. Its totient is φ = 112001121009982.
The previous prime is 112001121009971. The next prime is 112001121010019. The reversal of 112001121009983 is 389900121100211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112001121009983 - 218 = 112001120747839 is a prime.
It is a super-2 number, since 2×1120011210099832 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112001121009383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000560504991 + 56000560504992.
It is an arithmetic number, because the mean of its divisors is an integer number (56000560504992).
Almost surely, 2112001121009983 is an apocalyptic number.
112001121009983 is a deficient number, since it is larger than the sum of its proper divisors (1).
112001121009983 is an equidigital number, since it uses as much as digits as its factorization.
112001121009983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 38.
The spelling of 112001121009983 in words is "one hundred twelve trillion, one billion, one hundred twenty-one million, nine thousand, nine hundred eighty-three".
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