11200120123 has 2 divisors, whose sum is σ = 11200120124. Its totient is φ = 11200120122.

The previous prime is 11200120121. The next prime is 11200120153. The reversal of 11200120123 is 32102100211.

11200120123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11200120123 - 2¹ = 11200120121 is a prime.

Together with 11200120121, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (11200120121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600060061 + 5600060062.

It is an arithmetic number, because the mean of its divisors is an integer number (5600060062).

Almost surely, 2^11200120123 is an apocalyptic number.

11200120123 is a deficient number, since it is larger than the sum of its proper divisors (1).

11200120123 is an equidigital number, since it uses as much as digits as its factorization.

11200120123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11200120123 its reverse (32102100211), we get a palindrome (43302220334).

The spelling of 11200120123 in words is "eleven billion, two hundred million, one hundred twenty thousand, one hundred twenty-three".