Base | Representation |
---|---|
bin | 11001011101110101010000… |
… | …111111111000101001000111 |
3 | 112200120012201200010001022202 |
4 | 121131311100333320221013 |
5 | 104140012000100232101 |
6 | 1034112352313145115 |
7 | 32406551445312323 |
oct | 3135652077705107 |
9 | 480505650101282 |
10 | 112001221102151 |
11 | 327614a64a0107 |
12 | 1068a7063bb19b |
13 | 4a65892807c84 |
14 | 1d92c60a54983 |
15 | ce361e9e836b |
hex | 65dd50ff8a47 |
112001221102151 has 2 divisors, whose sum is σ = 112001221102152. Its totient is φ = 112001221102150.
The previous prime is 112001221102117. The next prime is 112001221102153. The reversal of 112001221102151 is 151201122100211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112001221102151 - 26 = 112001221102087 is a prime.
Together with 112001221102153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112001221102153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56000610551075 + 56000610551076.
It is an arithmetic number, because the mean of its divisors is an integer number (56000610551076).
Almost surely, 2112001221102151 is an apocalyptic number.
112001221102151 is a deficient number, since it is larger than the sum of its proper divisors (1).
112001221102151 is an equidigital number, since it uses as much as digits as its factorization.
112001221102151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 112001221102151 its reverse (151201122100211), we get a palindrome (263202343202362).
The spelling of 112001221102151 in words is "one hundred twelve trillion, one billion, two hundred twenty-one million, one hundred two thousand, one hundred fifty-one".
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