Base | Representation |
---|---|
bin | 11001011101111101011101… |
… | …011101000001001110110101 |
3 | 112200121001102212210101222221 |
4 | 121131331131131001032311 |
5 | 104140133010110010233 |
6 | 1034120405352122341 |
7 | 32410312466600623 |
oct | 3135753535011665 |
9 | 480531385711887 |
10 | 112010020000693 |
11 | 32765201216891 |
12 | 106903610963b1 |
13 | 4a66665706809 |
14 | 1d9345747c513 |
15 | ce39871ee42d |
hex | 65df5d7413b5 |
112010020000693 has 2 divisors, whose sum is σ = 112010020000694. Its totient is φ = 112010020000692.
The previous prime is 112010020000661. The next prime is 112010020000729. The reversal of 112010020000693 is 396000020010211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 76443860995524 + 35566159005169 = 8743218^2 + 5963737^2 .
It is a cyclic number.
It is not a de Polignac number, because 112010020000693 - 25 = 112010020000661 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112010020000633) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005010000346 + 56005010000347.
It is an arithmetic number, because the mean of its divisors is an integer number (56005010000347).
Almost surely, 2112010020000693 is an apocalyptic number.
It is an amenable number.
112010020000693 is a deficient number, since it is larger than the sum of its proper divisors (1).
112010020000693 is an equidigital number, since it uses as much as digits as its factorization.
112010020000693 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 25.
The spelling of 112010020000693 in words is "one hundred twelve trillion, ten billion, twenty million, six hundred ninety-three", and thus it is an aban number.
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