Base | Representation |
---|---|
bin | 11001011101111101011101… |
… | …011101000001010011100001 |
3 | 112200121001102212210102102001 |
4 | 121131331131131001103201 |
5 | 104140133010110012433 |
6 | 1034120405352124001 |
7 | 32410312466601532 |
oct | 3135753535012341 |
9 | 480531385712361 |
10 | 112010020000993 |
11 | 32765201217034 |
12 | 10690361096601 |
13 | 4a666657069aa |
14 | 1d9345747c689 |
15 | ce39871ee57d |
hex | 65df5d7414e1 |
112010020000993 has 2 divisors, whose sum is σ = 112010020000994. Its totient is φ = 112010020000992.
The previous prime is 112010020000987. The next prime is 112010020001027. The reversal of 112010020000993 is 399000020010211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 61393226756689 + 50616793244304 = 7835383^2 + 7114548^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112010020000993 is a prime.
It is not a weakly prime, because it can be changed into another prime (112010020000693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56005010000496 + 56005010000497.
It is an arithmetic number, because the mean of its divisors is an integer number (56005010000497).
Almost surely, 2112010020000993 is an apocalyptic number.
It is an amenable number.
112010020000993 is a deficient number, since it is larger than the sum of its proper divisors (1).
112010020000993 is an equidigital number, since it uses as much as digits as its factorization.
112010020000993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
The spelling of 112010020000993 in words is "one hundred twelve trillion, ten billion, twenty million, nine hundred ninety-three", and thus it is an aban number.
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