Base | Representation |
---|---|
bin | 1010001011111111011011… |
… | …0010001101111100000111 |
3 | 1110122211001022121100021211 |
4 | 2202333312302031330013 |
5 | 2432004343221200403 |
6 | 35453420141152251 |
7 | 2234153124630313 |
oct | 242776662157407 |
9 | 43584038540254 |
10 | 11201120100103 |
11 | 362940631397a |
12 | 130aa2855b687 |
13 | 633351810a4b |
14 | 2aa1cc308b43 |
15 | 14657813506d |
hex | a2ff6c8df07 |
11201120100103 has 2 divisors, whose sum is σ = 11201120100104. Its totient is φ = 11201120100102.
The previous prime is 11201120100077. The next prime is 11201120100119. The reversal of 11201120100103 is 30100102110211.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11201120100103 - 213 = 11201120091911 is a prime.
It is a super-2 number, since 2×112011201001032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11201120100193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600560050051 + 5600560050052.
It is an arithmetic number, because the mean of its divisors is an integer number (5600560050052).
Almost surely, 211201120100103 is an apocalyptic number.
11201120100103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201120100103 is an equidigital number, since it uses as much as digits as its factorization.
11201120100103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 11201120100103 its reverse (30100102110211), we get a palindrome (41301222210314).
The spelling of 11201120100103 in words is "eleven trillion, two hundred one billion, one hundred twenty million, one hundred thousand, one hundred three".
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