Base | Representation |
---|---|
bin | 110100001010001110… |
… | …0010000000111001111 |
3 | 101201010022112020202001 |
4 | 1220110130100013033 |
5 | 3313400044200142 |
6 | 123242504013131 |
7 | 11043523066231 |
oct | 1502434200717 |
9 | 351108466661 |
10 | 112012100047 |
11 | 4355aa01711 |
12 | 198607611a7 |
13 | a74131c953 |
14 | 55c850c251 |
15 | 2da8a9a5b7 |
hex | 1a147101cf |
112012100047 has 2 divisors, whose sum is σ = 112012100048. Its totient is φ = 112012100046.
The previous prime is 112012100033. The next prime is 112012100059. The reversal of 112012100047 is 740001210211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112012100047 - 211 = 112012097999 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112012099997 and 112012100033.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112012100647) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006050023 + 56006050024.
It is an arithmetic number, because the mean of its divisors is an integer number (56006050024).
Almost surely, 2112012100047 is an apocalyptic number.
112012100047 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012100047 is an equidigital number, since it uses as much as digits as its factorization.
112012100047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 112012100047 its reverse (740001210211), we get a palindrome (852013310258).
The spelling of 112012100047 in words is "one hundred twelve billion, twelve million, one hundred thousand, forty-seven".
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