Base | Representation |
---|---|
bin | 11001011101111111011001… |
… | …011100011001000101100111 |
3 | 112200121020210212002001010212 |
4 | 121131333121130121011213 |
5 | 104140201240123223142 |
6 | 1034121352022210035 |
7 | 32410415156233061 |
oct | 3135773134310547 |
9 | 480536725061125 |
10 | 112012100211047 |
11 | 327660794686a3 |
12 | 1069084188391b |
13 | 4a66907685c0a |
14 | 1d935b3856731 |
15 | ce3a59b57d82 |
hex | 65dfd9719167 |
112012100211047 has 2 divisors, whose sum is σ = 112012100211048. Its totient is φ = 112012100211046.
The previous prime is 112012100210981. The next prime is 112012100211049. The reversal of 112012100211047 is 740112001210211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112012100211047 is a prime.
Together with 112012100211049, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112012100211049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006050105523 + 56006050105524.
It is an arithmetic number, because the mean of its divisors is an integer number (56006050105524).
Almost surely, 2112012100211047 is an apocalyptic number.
112012100211047 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012100211047 is an equidigital number, since it uses as much as digits as its factorization.
112012100211047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 112012100211047 its reverse (740112001210211), we get a palindrome (852124101421258).
The spelling of 112012100211047 in words is "one hundred twelve trillion, twelve billion, one hundred million, two hundred eleven thousand, forty-seven".
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