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112012111209883 is a prime number
BaseRepresentation
bin11001011101111111011010…
…000110010110010110011011
3112200121020211121202211201011
4121131333122012112112123
5104140201300432204013
61034121353054034351
732410415351562463
oct3135773206262633
9480536747684634
10112012111209883
11327660846a0245
12106908454a89b7
134a66909a372c1
141d935b50baba3
15ce3a5aacbc3d
hex65dfda19659b

112012111209883 has 2 divisors, whose sum is σ = 112012111209884. Its totient is φ = 112012111209882.

The previous prime is 112012111209833. The next prime is 112012111209923. The reversal of 112012111209883 is 388902111210211.

It is a happy number.

It is an a-pointer prime, because the next prime (112012111209923) can be obtained adding 112012111209883 to its sum of digits (40).

It is a strong prime.

It is an emirp because it is prime and its reverse (388902111210211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112012111209883 - 217 = 112012111078811 is a prime.

It is not a weakly prime, because it can be changed into another prime (112012111209833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006055604941 + 56006055604942.

It is an arithmetic number, because the mean of its divisors is an integer number (56006055604942).

Almost surely, 2112012111209883 is an apocalyptic number.

112012111209883 is a deficient number, since it is larger than the sum of its proper divisors (1).

112012111209883 is an equidigital number, since it uses as much as digits as its factorization.

112012111209883 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 40.

The spelling of 112012111209883 in words is "one hundred twelve trillion, twelve billion, one hundred eleven million, two hundred nine thousand, eight hundred eighty-three".