Base | Representation |
---|---|
bin | 11001011101111111011010… |
… | …101100011101100111011111 |
3 | 112200121020212022120110002221 |
4 | 121131333122230131213133 |
5 | 104140201311011413434 |
6 | 1034121354052130211 |
7 | 32410415532524446 |
oct | 3135773254354737 |
9 | 480536768513087 |
10 | 112012121201119 |
11 | 3276608a2a4867 |
12 | 10690848906967 |
13 | 4a6690bb24b89 |
14 | 1d935b655bd5d |
15 | ce3a5b9022b4 |
hex | 65dfdab1d9df |
112012121201119 has 2 divisors, whose sum is σ = 112012121201120. Its totient is φ = 112012121201118.
The previous prime is 112012121201111. The next prime is 112012121201137. The reversal of 112012121201119 is 911102121210211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112012121201119 - 23 = 112012121201111 is a prime.
It is a super-2 number, since 2×1120121212011192 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 112012121201093 and 112012121201102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112012121201111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56006060600559 + 56006060600560.
It is an arithmetic number, because the mean of its divisors is an integer number (56006060600560).
Almost surely, 2112012121201119 is an apocalyptic number.
112012121201119 is a deficient number, since it is larger than the sum of its proper divisors (1).
112012121201119 is an equidigital number, since it uses as much as digits as its factorization.
112012121201119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 25.
The spelling of 112012121201119 in words is "one hundred twelve trillion, twelve billion, one hundred twenty-one million, two hundred one thousand, one hundred nineteen".
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