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1120124333401 is a prime number
BaseRepresentation
bin10000010011001100100…
…111001110110101011001
310222002020101112211100021
4100103030213032311121
5121323003312132101
62214324503510441
7143632503511333
oct20231447166531
93862211484307
101120124333401
113a2050a91597
12161107458421
1381820166368
143c3000b6453
151e20c5cb5a1
hex104cc9ced59

1120124333401 has 2 divisors, whose sum is σ = 1120124333402. Its totient is φ = 1120124333400.

The previous prime is 1120124333399. The next prime is 1120124333459. The reversal of 1120124333401 is 1043334210211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 978864869376 + 141259464025 = 989376^2 + 375845^2 .

It is an emirp because it is prime and its reverse (1043334210211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1120124333401 - 21 = 1120124333399 is a prime.

Together with 1120124333399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1120122333401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560062166700 + 560062166701.

It is an arithmetic number, because the mean of its divisors is an integer number (560062166701).

Almost surely, 21120124333401 is an apocalyptic number.

It is an amenable number.

1120124333401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120124333401 is an equidigital number, since it uses as much as digits as its factorization.

1120124333401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1120124333401 its reverse (1043334210211), we get a palindrome (2163458543612).

The spelling of 1120124333401 in words is "one trillion, one hundred twenty billion, one hundred twenty-four million, three hundred thirty-three thousand, four hundred one".