Base | Representation |
---|---|
bin | 10000010011001100100… |
… | …111001110110101011001 |
3 | 10222002020101112211100021 |
4 | 100103030213032311121 |
5 | 121323003312132101 |
6 | 2214324503510441 |
7 | 143632503511333 |
oct | 20231447166531 |
9 | 3862211484307 |
10 | 1120124333401 |
11 | 3a2050a91597 |
12 | 161107458421 |
13 | 81820166368 |
14 | 3c3000b6453 |
15 | 1e20c5cb5a1 |
hex | 104cc9ced59 |
1120124333401 has 2 divisors, whose sum is σ = 1120124333402. Its totient is φ = 1120124333400.
The previous prime is 1120124333399. The next prime is 1120124333459. The reversal of 1120124333401 is 1043334210211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 978864869376 + 141259464025 = 989376^2 + 375845^2 .
It is an emirp because it is prime and its reverse (1043334210211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1120124333401 - 21 = 1120124333399 is a prime.
Together with 1120124333399, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1120122333401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560062166700 + 560062166701.
It is an arithmetic number, because the mean of its divisors is an integer number (560062166701).
Almost surely, 21120124333401 is an apocalyptic number.
It is an amenable number.
1120124333401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1120124333401 is an equidigital number, since it uses as much as digits as its factorization.
1120124333401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1120124333401 its reverse (1043334210211), we get a palindrome (2163458543612).
The spelling of 1120124333401 in words is "one trillion, one hundred twenty billion, one hundred twenty-four million, three hundred thirty-three thousand, four hundred one".
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