Base | Representation |
---|---|
bin | 1010001100000000001001… |
… | …0000010010001000110111 |
3 | 1110122211112201200211212001 |
4 | 2203000002100102020313 |
5 | 2432010242001442444 |
6 | 35453451213440131 |
7 | 2234160652361323 |
oct | 243000220221067 |
9 | 43584481624761 |
10 | 11201312530999 |
11 | 36294a49a7078 |
12 | 130aa80aa0047 |
13 | 633382647a96 |
14 | 2aa209aba983 |
15 | 146589e968d4 |
hex | a3002412237 |
11201312530999 has 2 divisors, whose sum is σ = 11201312531000. Its totient is φ = 11201312530998.
The previous prime is 11201312530997. The next prime is 11201312531063. The reversal of 11201312530999 is 99903521310211.
It is a weak prime.
It is an emirp because it is prime and its reverse (99903521310211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11201312530999 - 21 = 11201312530997 is a prime.
Together with 11201312530997, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11201312530997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5600656265499 + 5600656265500.
It is an arithmetic number, because the mean of its divisors is an integer number (5600656265500).
Almost surely, 211201312530999 is an apocalyptic number.
11201312530999 is a deficient number, since it is larger than the sum of its proper divisors (1).
11201312530999 is an equidigital number, since it uses as much as digits as its factorization.
11201312530999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 131220, while the sum is 46.
The spelling of 11201312530999 in words is "eleven trillion, two hundred one billion, three hundred twelve million, five hundred thirty thousand, nine hundred ninety-nine".
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