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1120132224373 is a prime number
BaseRepresentation
bin10000010011001101000…
…101010101010101110101
310222002020221101201201111
4100103031011111111311
5121323012322134443
62214325344555021
7143632630545151
oct20231505252565
93862227351644
101120132224373
113a2055491158
1216110a022a71
1381821999c86
143c30116c061
151e20d13969d
hex104cd155575

1120132224373 has 2 divisors, whose sum is σ = 1120132224374. Its totient is φ = 1120132224372.

The previous prime is 1120132224371. The next prime is 1120132224439. The reversal of 1120132224373 is 3734222310211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 829888204324 + 290244020049 = 910982^2 + 538743^2 .

It is a cyclic number.

It is not a de Polignac number, because 1120132224373 - 21 = 1120132224371 is a prime.

Together with 1120132224371, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1120132224371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560066112186 + 560066112187.

It is an arithmetic number, because the mean of its divisors is an integer number (560066112187).

Almost surely, 21120132224373 is an apocalyptic number.

It is an amenable number.

1120132224373 is a deficient number, since it is larger than the sum of its proper divisors (1).

1120132224373 is an equidigital number, since it uses as much as digits as its factorization.

1120132224373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 1120132224373 its reverse (3734222310211), we get a palindrome (4854354534584).

The spelling of 1120132224373 in words is "one trillion, one hundred twenty billion, one hundred thirty-two million, two hundred twenty-four thousand, three hundred seventy-three".