Search a number
-
+
11202002111213 is a prime number
BaseRepresentation
bin1010001100000010101101…
…0110110100101011101101
31110122220022210021011001222
42203000223112310223231
52432013200020024323
635454043445513125
72234214024614264
oct243005326645355
943586283234058
1011202002111213
113629819179981
12130b033a127a5
13633462479504
142aa2735015db
151465ca7ab9c8
hexa302b5b4aed

11202002111213 has 2 divisors, whose sum is σ = 11202002111214. Its totient is φ = 11202002111212.

The previous prime is 11202002111171. The next prime is 11202002111243. The reversal of 11202002111213 is 31211120020211.

It is a happy number.

11202002111213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7015648771849 + 4186353339364 = 2648707^2 + 2046058^2 .

It is a cyclic number.

It is not a de Polignac number, because 11202002111213 - 234 = 11184822242029 is a prime.

It is a super-3 number, since 3×112020021112133 (a number of 40 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 11202002111191 and 11202002111200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11202002111243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5601001055606 + 5601001055607.

It is an arithmetic number, because the mean of its divisors is an integer number (5601001055607).

Almost surely, 211202002111213 is an apocalyptic number.

It is an amenable number.

11202002111213 is a deficient number, since it is larger than the sum of its proper divisors (1).

11202002111213 is an equidigital number, since it uses as much as digits as its factorization.

11202002111213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11202002111213 its reverse (31211120020211), we get a palindrome (42413122131424).

The spelling of 11202002111213 in words is "eleven trillion, two hundred two billion, two million, one hundred eleven thousand, two hundred thirteen".